Weighted estimates for the averaging integral operator
- Autores: Bohumír Opic, Jiri Rakosnik
- Localización: Collectanea mathematica, ISSN 0010-0757, Vol. 61, Fasc. 3, 2010, págs. 253-262
- Idioma: inglés
- DOI: 10.1007/bf03191231
- Enlaces
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Resumen
Let $1 satisfying:
\hskip-5cm \begin{align} (\star)\qquad &v(x)x^{\rho} \text{is equivalent to a non-decreasing function on}\ (0,+\infty)\nonumber\\ &\text{for some}\ \rho \ge 0;\nonumber \end{align}\[ \qquad [w(x)x]^{1/q}\approx [v(x)x]^{1/p} \quad \text{for all } x\in(0,+\infty).
\] We prove that if the averaging operator $(Af)(x):=\frac1x\int_0^x f(t)\,dt$, $x \in (0,+\infty)$, is bounded from the weighted Lebesgue space $L^p((0,+\infty);v)$ into the weighted Lebesgue space $L^q((0,+\infty);w)$, then there exists $\varepsilon_0\in(0,p-1)$ such that the operator $A$ is also bounded from the space $L^{p-\varepsilon}((0,+\infty);v(x)^{1+\delta}x^\gamma)$ into the space $L^{q-\varepsilon q/p}((0,+\infty);w(x)^{1+\delta}x^{\delta(1-q/p)}x^{\gamma q/p})$ for all $\varepsilon, \delta, \gamma\in[0,\varepsilon_0)$.
Conversely, assuming that the operator \[A : L^{p-\varepsilon}((0,+\infty);v(x)^{1+\delta}x^\gamma)\rightarrow L^{q-\varepsilon q/p}((0,+\infty);w(x)^{1+\delta}x^{\delta(1-q/p)}x^{\gamma q/p}) \] is bounded for some $\varepsilon\in[0,p-1)$, $\delta\ge0$ and $\gamma\ge0$, we prove that the operator $A$ is also bounded from the space $L^p((0,+\infty);v)$ into the space $L^q((0,+\infty);w)$.
In particular, our results imply that the class of weights $v$ for which ($\star$) holds and the operator $A$ is bounded on the space $L^p((0,+\infty);v)$ possesses similar properties to those of the $A_p$-class of B. Muckenhoupt.
