Abstract
We prove that for a commutative ring with \(1 \ne 0\), if it is consistently \(L^{*}\), then it is consistently \(O^{*}\). An example is provided to show that a consistently \(O^{*}\)-ring may not be \(O^{*}\).
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Dedicated to Professor Stuart Steinberg on the occasion of his 80th birthday.
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Ma, J. Commutative consistently \(L^{*}\)-rings. Algebra Univers. 80, 31 (2019). https://doi.org/10.1007/s00012-019-0604-6
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DOI: https://doi.org/10.1007/s00012-019-0604-6
Keywords
- Commutative ring
- Consistently \(L^{*}\)-ring
- Consistently \(O^{*}\)-ring
- Division closed
- \(L^{*}\)-ring
- \(O^{*}\)-ring